(0.5)^x=(0.5)^1-x

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Solution for (0.5)^x=(0.5)^1-x equation: 



(0.5)^x=(0.5)^1-x

We move all terms to the left:

(0.5)^x-((0.5)^1-x)=0



We calculate terms in parentheses: -((0.5)^1-x), so:

(0.5)^1-x

determiningTheFunctionDomain
-x+(0.5)^1

We add all the numbers together, and all the variables

-1x+0.5

Back to the equation:

-(-1x+0.5)



We get rid of parentheses

(0.5)^x+1x-0.5=0

We add all the numbers together, and all the variables

x+(0.5)^x-0.5=0

We move all terms containing x to the left, all other terms to the right

x+(0.5)^x=0.5

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